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प्रश्न
from the following pair would undergo SN2 faster from the other?
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उत्तर
Compound (a) will undergo SN2 mechanism faster than (b).
Explanation:
- Sincey
is a primary halide it undergoes S2N reaction faster than 
. - Since iodine is a better leaving group than chloride, 1-iodo propane (CH3CH2CH2I) undergoes S2N reaction faster than l-chloropropane (CH3CH2CH2CI).
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संबंधित प्रश्न
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- 2- Bromopropane
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\[\ce{\underset{Ethyl bromide}{C2H5Br} + \underset{(aq.)}{KOH} ->[\Delta] \underset{Ethyl alcohol}{C2H5OH} + KBr}\]
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\[\begin{array}{cc}
\ce{CH3}\phantom{.................}\\
|\phantom{...................}\\
\ce{CH3 - C - CH2 - Cl->[Na/dry ether]A}\\
|\phantom{..................}\\
\ce{CH3}\phantom{................}
\end{array}\]
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\[\ce{CH3CH2Cl ->[AgCN][alc.\Delta]}\] ?
Complete the following reaction giving major product.
\[\begin{array}{cc}
\ce{CH3}\phantom{................}\\
|\phantom{...................}\\
\ce{CH3 - C - CH2 - Cl->[Na/ dry ether]A}\\
|\phantom{...................}\\
\ce{CH3}\phantom{................}\\
\end{array}\]
Complete the following reaction giving major product.
\[\begin{array}{cc}
\ce{CH3}\phantom{.................}\\
|\phantom{...................}\\
\ce{CH3 - C - CH2 - Cl ->[Na/dry ether] A}\\
|\phantom{...................}\\
\ce{CH3}\phantom{.................}\\
\end{array}\]
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