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प्रश्न
from the following pair would undergo SN2 faster from the other?
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उत्तर
Compound (a) will undergo SN2 mechanism faster than (b).
Explanation:
- Sincey
is a primary halide it undergoes S2N reaction faster than 
. - Since iodine is a better leaving group than chloride, 1-iodo propane (CH3CH2CH2I) undergoes S2N reaction faster than l-chloropropane (CH3CH2CH2CI).
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संबंधित प्रश्न
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\[\begin{array}{cc}
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|\\
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|\\
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\[\begin{array}{cc}
\ce{CH3}\phantom{.......}\\
|\phantom{.........}\\
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\ce{CH3}\phantom{.................}\\
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\ce{CH3}\phantom{................}\\
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|\phantom{...................}\\
\ce{CH3}\phantom{................}
\end{array}\]
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\[\begin{array}{cc}
\ce{CH3}\phantom{...............}\\
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\ce{CH3}\phantom{.................}
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\[\begin{array}{cc}
\ce{CH3}\phantom{................}\\
|\phantom{...................}\\
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|\phantom{...................}\\
\ce{CH3}\phantom{................}\\
\end{array}\]
