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प्रश्न
from the following pair would undergo SN2 faster from the other?
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उत्तर
Compound (a) will undergo SN2 mechanism faster than (b).
Explanation:
- Sincey
is a primary halide it undergoes S2N reaction faster than 
. - Since iodine is a better leaving group than chloride, 1-iodo propane (CH3CH2CH2I) undergoes S2N reaction faster than l-chloropropane (CH3CH2CH2CI).
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\[\begin{array}{cc}\ce{CH3 - CH = CH3 ->[Red P/Br2] A ->[Ag2O/H2O]B}\\|\phantom{.........................}\\
\ce{OH\phantom{.......................}}\end{array}\]
Complete the following reaction giving major product.
\[\begin{array}{cc}\ce{CH3\phantom{................}}\\
|\phantom{...................}\\
\ce{CH3 - C - CH2 - Cl ->[Na/dry ether] A}\\
|\phantom{...................}\\
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\[\begin{array}{cc}
\ce{CH3}\phantom{.......}\\
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\[\begin{array}{cc}
\ce{CH3}\phantom{.................}\\
|\phantom{...................}\\
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\[\begin{array}{cc}
\ce{CH3}\phantom{................}\\
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|\phantom{...................}\\
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\[\begin{array}{cc}
\ce{CH3}\phantom{...............}\\
|\phantom{..................}\\
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\[\begin{array}{cc}
\ce{CH3}\phantom{................}\\
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\[\begin{array}{cc}
\ce{CH3}\phantom{.................}\\
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