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For Any Two Vectors → a and → B Show that ( → a + → B ) ⋅ ( → a − → B ) = 0 ⇔ | → a | = ∣ ∣ → B ∣ ∣

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प्रश्न

For any two vectors \[\vec{a} \text{ and } \vec{b}\] show that \[\left( \vec{a} + \vec{b} \right) \cdot \left( \vec{a} - \vec{b} \right) = 0 \Leftrightarrow \left| \vec{a} \right| = \left| \vec{b} \right|\]

योग
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उत्तर

\[\text{ We have }\]
\[\left( \vec{a} + \vec{b} \right) . \left( \vec{a} - \vec{b} \right) = 0\]
\[ \Rightarrow \left| \vec{a} \right|^2 - \left| \vec{b} \right|^2 = 0\]
\[ \Rightarrow \left| \vec{a} \right|^2 = \left| \vec{b} \right|^2 \]
\[ \Rightarrow \left| \vec{a} \right| = \left| \vec{b} \right|\]

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अध्याय 23: Scalar Or Dot Product - Exercise 24.1 [पृष्ठ ३०]

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आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
अध्याय 23 Scalar Or Dot Product
Exercise 24.1 | Q 14 | पृष्ठ ३०

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