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Express → a B in Terms of Unit Vectors ^ I and ^ J , When the Points Are a (−6, 3), B (−2, −5) Find ∣ ∣ → a B ∣ ∣ in Each Case.

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प्रश्न

Express \[\vec{AB}\]  in terms of unit vectors \[\hat{i}\] and \[\hat{j}\], when the points are A (−6, 3), B (−2, −5)
Find \[\left| \vec{A} B \right|\] in each case.

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उत्तर

Given: \[A\left( - 6, 3 \right)\] and \[B \left( - 2, - 5 \right)\] 
Then, the position vector \[\vec{AB}\]  is given by \[\vec{AB} =\] Position vector of  B - Position vector of A
\[= \left( - 2 \hat{i} - 5 \hat{j} \right) - \left( - 6 \hat{i} + 3 \hat{j} \right)\]
\[ = - 2 \hat{i} - 5 \hat{j} + 6 \hat{i} - 3 \hat{j} \]
\[ = 4 \hat{i} - 8 \hat{j}\]
So, 
\[\left| \vec{AB} \right| = \sqrt{4^2 + \left( - 8 \right)^2} = \sqrt{16 + 64} = \sqrt{80} = 4\sqrt{5}\]

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 22: Algebra of Vectors - Exercise 23.4 [पृष्ठ ४२]

APPEARS IN

आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
अध्याय 22 Algebra of Vectors
Exercise 23.4 | Q 4.2 | पृष्ठ ४२

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