हिंदी

Following table shows a frequency distribution for the speed of cars passing through at a particular spot on a high way: Class interval (km/h) Frequency 30 – 40 3 40 – 50 6 50 – 60 25 60 – 70 65

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प्रश्न

Following table shows a frequency distribution for the speed of cars passing through at a particular spot on a high way:

Class interval (km/h) Frequency
30 – 40 3
40 – 50 6
50 – 60 25
60 – 70 65
70 – 80 50
80 – 90 28
90 – 100 14

Draw the frequency polygon representing the above data without drawing the histogram.

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उत्तर

First we obtain in the class marks (mid-marks) of the given table as:

Class-marks = `("Lower limit" + "Upper limit")/2`

Since, the new table is shown below:

Class interval Class marks Frequency
30 – 40 35 3
40 – 50 45 6
50 – 60 55 25
60 – 70 65 65
70 – 80 75 50
80 – 90 85 28
90 – 100 95 14

Now, let’s draw a frequency polygon by plotting the class marks along the x-axis and the frequency along y-axis.

Also, plotting all the points as B(35, 3), C(45, 6), (D(55, 25), E(65, 65), F(75, 50), G(85, 28) and H(95, 14). 

Then join all these point line segment, shown below:

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अध्याय 14: Statistics & Probability - Exercise 14.4 [पृष्ठ १४९]

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एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 9
अध्याय 14 Statistics & Probability
Exercise 14.4 | Q 8. | पृष्ठ १४९

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