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प्रश्न
Following table shows a frequency distribution for the speed of cars passing through at a particular spot on a high way:
| Class interval (km/h) | Frequency |
| 30 – 40 | 3 |
| 40 – 50 | 6 |
| 50 – 60 | 25 |
| 60 – 70 | 65 |
| 70 – 80 | 50 |
| 80 – 90 | 28 |
| 90 – 100 | 14 |
Draw the frequency polygon representing the above data without drawing the histogram.
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उत्तर
First we obtain in the class marks (mid-marks) of the given table as:
Class-marks = `("Lower limit" + "Upper limit")/2`
Since, the new table is shown below:
| Class interval | Class marks | Frequency |
| 30 – 40 | 35 | 3 |
| 40 – 50 | 45 | 6 |
| 50 – 60 | 55 | 25 |
| 60 – 70 | 65 | 65 |
| 70 – 80 | 75 | 50 |
| 80 – 90 | 85 | 28 |
| 90 – 100 | 95 | 14 |
Now, let’s draw a frequency polygon by plotting the class marks along the x-axis and the frequency along y-axis.
Also, plotting all the points as B(35, 3), C(45, 6), (D(55, 25), E(65, 65), F(75, 50), G(85, 28) and H(95, 14).
Then join all these point line segment, shown below:
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संबंधित प्रश्न
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| Loan (in crores of rupees) |
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| Year | 1950-51 | 1960-61 | 1965-66 | 1970-71 | 1980-81 | 1982-83 |
| Quantity of Goods (in crore tonnes) |
9 | 16 | 20 | 20 | 22 | 26 |
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| Expenditure (in Rs): |
100-150 | 150-200 | 200-250 | 250-300 | 300-350 | 350-400 | 400-450 | 450-500 |
| No. of manual workers: | 25 | 40 | 33 | 28 | 30 | 22 | 16 | 8 |
Draw a histogram and a frequency polygon representing the above data.
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| 230 | 400 | 350 | 200 | 380 | 160 |
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Represent the above data by drawing a suitable bar graph.
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Represent the information above by a bar graph.
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