Advertisements
Advertisements
प्रश्न
Find the value of ` ( sin 50°)/(cos 40°)+ (cosec 40°)/(sec 50°) - 4 cos 50° cosec 40 °`
Advertisements
उत्तर
`(sin 50°)/(cos 40 °)+ ( cosec 40° )/( sec 50°) - 4 cos 50° cosec 40°`
`=(cos (90°- 50°))/(cos 40°) + (sec (90°- 40°))/(sec 50°)- 4 sin (90°-50°) cosec 40°`
`=(cos 40° )/( cos 40 °) + ( sec50°)/( sec 50°) - 4 sin 40 ° xx 1/ ( sin 40 °)`
= 1 + 1 - 4
= - 2
APPEARS IN
संबंधित प्रश्न
if `cos theta = 5/13` where `theta` is an acute angle. Find the value of `sin theta`
If sin A + cos A = p and sec A + cosec A = q, then prove that : q(p2 – 1) = 2p.
`cot theta/((cosec theta + 1) )+ ((cosec theta +1 ))/ cot theta = 2 sec theta `
`(sec theta -1 )/( sec theta +1) = ( sin ^2 theta)/( (1+ cos theta )^2)`
` (sin theta - cos theta) / ( sin theta + cos theta ) + ( sin theta + cos theta ) / ( sin theta - cos theta ) = 2/ ((2 sin^2 theta -1))`
If` (sec theta + tan theta)= m and ( sec theta - tan theta ) = n ,` show that mn =1
Write the value of ` sec^2 theta ( 1+ sintheta )(1- sintheta).`
Write the value of `3 cot^2 theta - 3 cosec^2 theta.`
Eliminate θ, if
x = 3 cosec θ + 4 cot θ
y = 4 cosec θ – 3 cot θ
\[\frac{1 - \sin \theta}{\cos \theta}\] is equal to
Prove the following identity :
`(1 + tan^2A) + (1 + 1/tan^2A) = 1/(sin^2A - sin^4A)`
Prove the following identity :
`(cosecθ)/(tanθ + cotθ) = cosθ`
Given `cos38^circ sec(90^circ - 2A) = 1` , Find the value of <A
Prove that `sinA/sin(90^circ - A) + cosA/cos(90^circ - A) = sec(90^circ - A) cosec(90^circ - A)`
If sin θ + cos θ = `sqrt(3)`, then prove that tan θ + cot θ = 1.
If `tan θ = 13/12`, then cot θ = ?
Prove that `(cos(90^circ - A))/(sin A) = (sin(90^circ - A))/(cos A)`.
Prove that `1/("cosec" θ - cot θ) = "cosec" θ + cot θ`.
If cos A + cos2A = 1, then sin2A + sin4A = ?
Which of the following is true for all values of θ (0° ≤ θ ≤ 90°)?
