हिंदी

`(Sec Theta -1 )/( Sec Theta +1) = ( Sin ^2 Theta)/( (1+ Cos Theta )^2)`

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प्रश्न

`(sec theta -1 )/( sec theta +1) = ( sin ^2 theta)/( (1+ cos theta )^2)`

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उत्तर

LHS  = `(sec theta-1)/(sec theta+1)`

         =` (1/cos theta-1)/(1/ cos theta +1)`

         =`((1-cos theta)/cos theta)/((1+ cos theta)/cos theta)`

         =`(1-cos theta)/(1+costheta)`

        =`((1-cos theta)(1+ cos theta))/((1+ cos theta)(1+ cos theta))    {"Dividing the numerator and
denominator by "(1+ cos theta)}`

       =`(1- cos^2 theta)/((1+ cos theta )^2)`

       =`(sin^2 theta)/((1+ cos theta) ^2)`

      = RHS

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अध्याय 13: Trigonometric identities - Exercises 1

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आर.एस. अग्रवाल Mathematics [English] Class 10
अध्याय 13 Trigonometric identities
Exercises 1 | Q 20.1

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