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प्रश्न
Find the zeroes of the quadratic polynomial (3x2 – x – 4) and verify the relation between the zeroes and the coefficients.
Find the zeros of the following quadratic polynomial and verify the relationship between the zeros and the coefficients:
3x2 – x – 4
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उत्तर
3x2 – x – 4 = 0
⇒ 3x2 – 4x + 3x – 4 = 0
⇒ x(3x – 4) + 1(3x – 4) = 0
⇒ (3x – 4) (x + 1) = 0
⇒ (3x – 4) or (x + 1) = 0
⇒ `x = 4/3` or x = –1
Sum of zeroes = `4/3 + (-1)`
= `1/3`
= `(-("Coefficient of" x))/(("Coefficient of" x^2))`
Product of zeroes = `4/3 xx (-1)`
= `(-4)/3`
= `("Constant term") /(("Coefficient of "x^2))`
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