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Find the derivatives of the following: If y = etan–1x, show that (1 + x2)y” + (2x – 1)y’ = 0

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प्रश्न

Find the derivatives of the following:

If y = etan–1x, show that (1 + x2)y” + (2x – 1)y’ = 0

योग
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उत्तर

y = etan–1x

y = `"e"^(tan - 1x)  (1/(1 + x^2))`

⇒ y’ = `y/(1 + x^2)`

⇒ y'(1 + x2) = y

Differentiating w.r.to x

y’ (2x) + (1 + x2)(y”) = y’

(i.e.) (1 + x2)y” + y’(2x) – y’ = 0

(i.e.) (1 + x2)y” + (2x – 1)y’ = 0

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Differentiation Rules
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 10: Differential Calculus - Differentiability and Methods of Differentiation - Exercise 10.4 [पृष्ठ १७६]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 10 Differential Calculus - Differentiability and Methods of Differentiation
Exercise 10.4 | Q 24 | पृष्ठ १७६

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