Advertisements
Advertisements
प्रश्न
Find the derivatives of the following:
If y = sin–1x then find y”
Advertisements
उत्तर
y = sin–1x
y" = `1/sqrt(1 - x^2)`
y" = `(1 - x^2)^(- 1/2)`
y" = `- 1/2 (1 - x^2)^(- 1/2 - 1) (0 - 2x)`
y" = `- 1/2 (1 - x^2)^(- 3/2) xx - 2x`
y" = `x/(1 - x^2)^(3/2)`
APPEARS IN
संबंधित प्रश्न
Find the derivatives of the following functions with respect to corresponding independent variables:
y = `tan x/x`
Find the derivatives of the following functions with respect to corresponding independent variables:
y = x sin x cos x
Find the derivatives of the following functions with respect to corresponding independent variables:
y = (x2 + 5) log(1 + x) e–3x
Differentiate the following:
y = tan 3x
Differentiate the following:
y = `x"e"^(-x^2)`
Differentiate the following:
y = tan (cos x)
Differentiate the following:
y = sin2(cos kx)
Differentiate the following:
y = `sqrt(x +sqrt(x)`
Differentiate the following:
y = `"e"^(xcosx)`
Find the derivatives of the following:
y = `x^(logx) + (logx)^x`
Find the derivatives of the following:
`sqrt(x) = "e"^((x - y))`
Find the derivatives of the following:
xy = yx
Find the derivatives of the following:
tan (x + y) + tan (x – y) = x
Find the derivatives of the following:
If u = `tan^-1 (sqrt(1 + x^2) - 1)/x` and v = `tan^-1 x`, find `("d"u)/("d"v)`
Choose the correct alternative:
x = `(1 - "t"^2)/(1 + "t"^2)`, y = `(2"t")/(1 + "t"^2)` then `("d"y)/("d"x)` is
Choose the correct alternative:
If x = a sin θ and y = b cos θ, then `("d"^2y)/("d"x^2)` is
Choose the correct alternative:
If y = `(1 - x)^2/x^2`, then `("d"y)/("d"x)` is
