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Differentiate the following:y = tan 3x

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प्रश्न

Differentiate the following:
y = tan 3x

योग
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उत्तर

y = tan 3x

Put u = 3x

`("d"u)/("d"x)` = 3

Now y = tan u

⇒ `("d"y)/("d"x)` = sec2u

So `("d"y)/("d"x) = ("d"y)/("d"u) xx ("d"u)/("d"x)` = (sec2 u)(3)

= 3 sec2 3x

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 10: Differential Calculus - Differentiability and Methods of Differentiation - Exercise 10.3 [पृष्ठ १६३]

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सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 10 Differential Calculus - Differentiability and Methods of Differentiation
Exercise 10.3 | Q 2 | पृष्ठ १६३

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