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Differentiate the following: f(t) = t1+tant3

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प्रश्न

Differentiate the following:

f(t) = `root(3)(1 + tan "t")`

योग
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उत्तर

f(t) = `root(3)(1 + tan "t")`

f(t) = `(1 + tan "t")^(1/3)`

[y = f(g(x)

`("d"y)/("d"x)` = f'(g(x)) . g'(x)]

`f"'"("t") = 1/3 (1 + tan "t")^(1/3 - 1) "d"/"dt" (1 + tan "t")`

= `1/3 (1 + tan "t")^(- 2/3) (0 + sec^2 "t")`

= `1/3 xx 1/(1 + tan "t")^(2/3) xx sec^2"t"`

= `(sec^2"t")/(3(1 + tan "t")^(2/3)`

`f"'"("t") = 1/2 sec^2"t" (1 + tan "t")^(- 2/3)`

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Differentiation Rules
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 10: Differential Calculus - Differentiability and Methods of Differentiation - Exercise 10.3 [पृष्ठ १६३]

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सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 10 Differential Calculus - Differentiability and Methods of Differentiation
Exercise 10.3 | Q 9 | पृष्ठ १६३

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