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प्रश्न
Differentiate the following:
y = `sqrt(1 + 2tanx)`
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उत्तर
y = `sqrt(1 + 2tanx)`
y = `(1 + 2 tan x)^(1/2)`
`("d"y)/("d"x) = 1/2(1 + 2 tan x)^(1/2 - 1) xx "d"/("d"x) (1 + 2 tan x)`
= `1/2 (1 + 2 tan x)^(- 1/2) xx (0 + 2 sec^2 x)`
= `1/(2(1 + 2 tan x)^(1/2)) xx 2sec^2x`
`("d"y)/("d"x) = (sec^2x)/sqrt(1 -+ 2 tanx)`
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