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Differentiate the following:y = eex

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प्रश्न

Differentiate the following:
y = `"e"^sqrt(x)`

योग
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उत्तर

y = `"e"^sqrt(x)`

y = `"e"^(x 1/2)`

[y = f(g(x)

`("d"y)/("d"x)` = f'(g(x)) . g'(x)]

`("d"y)/("d"x) = "e"^(x 1/2) xx "d"/("d"x) (x^(1/2))`

`("d"y)/("d"x) = "e"^sqrt(x) xx 1/2 xx x^(- 1/2)`

`("d"y)/("d"x) = 1/2 "e"^sqrt(x) xx 1/sqrt(x)`

`("d"y)/("d"x) = 1/(2sqrt(x))  "e"^sqrt(x)`

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 10: Differential Calculus - Differentiability and Methods of Differentiation - Exercise 10.3 [पृष्ठ १६३]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 10 Differential Calculus - Differentiability and Methods of Differentiation
Exercise 10.3 | Q 5 | पृष्ठ १६३

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