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तमिलनाडु बोर्ड ऑफ सेकेंडरी एज्युकेशनएचएससी विज्ञान कक्षा ११

Find the derivatives of the following functions with respect to corresponding independent variables: y = ex sin x

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प्रश्न

Find the derivatives of the following functions with respect to corresponding independent variables:

y = ex sin x

योग
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उत्तर

y = ex sin x

⇒ y = uv’ + vu’

Now u = ex

⇒ u’ = `("d"u)/("d"x) "e"^x`

v = sin x

⇒ v’ = `("d"v)/("d"x)` cos x

i.e. y’ = ex (cos x) + sin x (ex)

= ex [sin x + cos x]

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Differentiation Rules
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 10: Differential Calculus - Differentiability and Methods of Differentiation - Exercise 10.2 [पृष्ठ १६०]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 10 Differential Calculus - Differentiability and Methods of Differentiation
Exercise 10.2 | Q 7 | पृष्ठ १६०

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