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Find the derivative of x5 (3 – 6x–9).

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प्रश्न

Find the derivative of x5 (3 – 6x–9).

योग
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उत्तर

Let f (x) = x5 (3 – 6x–9)

By Leibnitz product rule,

f'(x) = `x^5 d/(dx) (3 - 6x^-9) + (3 - 6x^-9) d/(dx) (x^5)`

= x5 {0 - 6(-9)x-9-1} + (3 - 6x-9)(5x4)

= x5 (54x-10) + 15x4 - 30x-5

= 54x-5 + 15x4 - 30x-5

= 24x-5 + 15x4

= `15x^4 + 24/x^5`

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अध्याय 12: Limits and Derivatives - EXERCISE 12.2 [पृष्ठ २४९]

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एनसीईआरटी Mathematics [English] Class 11
अध्याय 12 Limits and Derivatives
EXERCISE 12.2 | Q 9. (iv) | पृष्ठ २४९

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