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प्रश्न
Find the derivative of x5 (3 – 6x–9).
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उत्तर
Let f (x) = x5 (3 – 6x–9)
By Leibnitz product rule,
f'(x) = `x^5 d/(dx) (3 - 6x^-9) + (3 - 6x^-9) d/(dx) (x^5)`
= x5 {0 - 6(-9)x-9-1} + (3 - 6x-9)(5x4)
= x5 (54x-10) + 15x4 - 30x-5
= 54x-5 + 15x4 - 30x-5
= 24x-5 + 15x4
= `15x^4 + 24/x^5`
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