मराठी

2 X + 3 X − 2

Advertisements
Advertisements

प्रश्न

\[\sqrt{2 x^2 + 1}\]

Advertisements

उत्तर

\[ \frac{d}{dx}\left( f(x) \right) = \lim_{h \to 0} \frac{f\left( x + h \right) - f\left( x \right)}{h}\]
\[ = \lim_{h \to 0} \frac{\sqrt{2 \left( x + h \right)^2 + 1} - \sqrt{2 x^2 + 1}}{h}\]
\[ = \lim_{h \to 0} \frac{\sqrt{2 x^2 + 2 h^2 + 4xh + 1} - \sqrt{2 x^2 + 1}}{h}\]
\[ = \lim_{h \to 0} \frac{\sqrt{2 x^2 + 2 h^2 + 4xh + 1} - \sqrt{2 x^2 + 1}}{h} \times \frac{\sqrt{2 x^2 + 2 h^2 + 4xh + 1} + \sqrt{2 x^2 + 1}}{\sqrt{2 x^2 + 2 h^2 + 4xh + 1} + \sqrt{2 x^2 + 1}}\]
\[ = \lim_{h \to 0} \frac{2 x^2 + 2 h^2 + 4xh + 1 - 2 x^2 - 1}{h\left( \sqrt{2 x^2 + 2 h^2 + 4xh + 1} + \sqrt{2 x^2 + 1} \right)}\]
\[ = \lim_{h \to 0} \frac{h\left( 2h + 4x \right)}{h\left( \sqrt{2 x^2 + 2 h^2 + 4xh + 1} + \sqrt{2 x^2 + 1} \right)}\]
\[ = \lim_{h \to 0} \frac{\left( 2h + 4x \right)}{\left( \sqrt{2 x^2 + 2 h^2 + 4xh + 1} + \sqrt{2 x^2 + 1} \right)}\]
\[ = \frac{4x}{\sqrt{2 x^2 + 1} + \sqrt{2 x^2 + 1}}\]
\[ = \frac{4x}{2\sqrt{2 x^2 + 1}}\]
\[ = \frac{2x}{\sqrt{2 x^2 + 1}}\]

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 30: Derivatives - Exercise 30.2 [पृष्ठ २५]

APPEARS IN

आर.डी. शर्मा Mathematics [English] Class 11
पाठ 30 Derivatives
Exercise 30.2 | Q 1.14 | पृष्ठ २५

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

Find the derivative of the following function (it is to be understood that a, b, c, d, p, q, r and s are fixed non-zero constants and m and n are integers):

`4sqrtx - 2`


Find the derivative of the following function (it is to be understood that a, b, c, d, p, q, r and s are fixed non-zero constants and m and n are integers):

`(sec x - 1)/(sec x + 1)`


Find the derivative of the following function at the indicated point:


\[\frac{x + 2}{3x + 5}\]


\[\frac{1}{\sqrt{3 - x}}\]


 (x2 + 1) (x − 5)


Differentiate each of the following from first principle:

ex


Differentiate  of the following from first principle:

 eax + b


x ex


Differentiate each of the following from first principle: 

sin x + cos x


Differentiate each of the following from first principle:

x2 e


Differentiate each of the following from first principle: 

\[e^{x^2 + 1}\]


Differentiate each of the following from first principle:

\[a^\sqrt{x}\]


tan (2x + 1) 


\[\frac{x^3}{3} - 2\sqrt{x} + \frac{5}{x^2}\]


ex log a + ea long x + ea log a


\[\frac{a \cos x + b \sin x + c}{\sin x}\]


a0 xn + a1 xn−1 + a2 xn2 + ... + an1 x + an


cos (x + a)


Find the slope of the tangent to the curve (x) = 2x6 + x4 − 1 at x = 1.


x3 sin 


(x sin x + cos x) (x cos x − sin x


(1 − 2 tan x) (5 + 4 sin x)


sin2 


x3 ex cos 


x4 (5 sin x − 3 cos x)


Differentiate each of the following functions by the product rule and the other method and verify that answer from both the methods is the same.

(x + 2) (x + 3)

 


Differentiate each of the following functions by the product rule and the other method and verify that answer from both the methods is the same.

(3 sec x − 4 cosec x) (−2 sin x + 5 cos x)


\[\frac{a x^2 + bx + c}{p x^2 + qx + r}\] 


\[\frac{1}{a x^2 + bx + c}\] 


\[\frac{x \tan x}{\sec x + \tan x}\]


\[\frac{a + \sin x}{1 + a \sin x}\] 


\[\frac{{10}^x}{\sin x}\] 


\[\frac{x + \cos x}{\tan x}\] 


\[\frac{ax + b}{p x^2 + qx + r}\] 


Write the value of \[\frac{d}{dx} \left\{ \left( x + \left| x \right| \right) \left| x \right| \right\}\]


Mark the correct alternative in of the following:
If \[f\left( x \right) = x^{100} + x^{99} + . . . + x + 1\]  then \[f'\left( 1 \right)\] is equal to 


Mark the correct alternative in  of the following:
If\[f\left( x \right) = 1 + x + \frac{x^2}{2} + . . . + \frac{x^{100}}{100}\] then \[f'\left( 1 \right)\] is equal to 


Find the derivative of f(x) = tan(ax + b), by first principle.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×