मराठी

1 √ X

Advertisements
Advertisements

प्रश्न

\[\frac{1}{\sqrt{x}}\]

Advertisements

उत्तर

\[ \frac{d}{dx}\left( f(x) \right) = \lim_{h \to 0} \frac{f\left( x + h \right) - f\left( x \right)}{h}\]
\[ = \lim_{h \to 0} \frac{\frac{1}{\sqrt{x + h}} - \frac{1}{\sqrt{x}}}{h}\]
\[ = \lim_{h \to 0} \frac{\sqrt{x} - \sqrt{x + h}}{h\sqrt{x}\sqrt{x + h}} \times \frac{\sqrt{x} + \sqrt{x + h}}{\sqrt{x} + \sqrt{x + h}}\]
\[ = \lim_{h \to 0} \frac{x - x - h}{h\sqrt{x}\sqrt{x + h}\left( \sqrt{x} + \sqrt{x + h} \right)}\]
\[ = \lim_{h \to 0} \frac{- h}{h\sqrt{x}\sqrt{x + h}\left( \sqrt{x} + \sqrt{x + h} \right)}\]
\[ = \lim_{h \to 0} \frac{- 1}{\sqrt{x}\sqrt{x + h}\left( \sqrt{x} + \sqrt{x + h} \right)}\]
\[ = \frac{- 1}{\sqrt{x}\sqrt{x}\left( \sqrt{x} + \sqrt{x} \right)}\]
\[ = \frac{- 1}{x \times 2\sqrt{x}}\]
\[ = \frac{- 1}{2 x^\frac{3}{2}}\]
\[ = - \frac{1}{2} x^\frac{- 3}{2} \]
\[\]

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 30: Derivatives - Exercise 30.2 [पृष्ठ २५]

APPEARS IN

आर.डी. शर्मा Mathematics [English] Class 11
पाठ 30 Derivatives
Exercise 30.2 | Q 1.02 | पृष्ठ २५

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

Find the derivative of x at x = 1.


Find the derivative of x–4 (3 – 4x–5).


Find the derivative of the following function (it is to be understood that a, b, c, d, p, q, r and s are fixed non-zero constants and m and n are integers):

(x + a)


Find the derivative of the following function (it is to be understood that a, b, c, d, p, q, r and s are fixed non-zero constants and m and n are integers):

`(px+ q) (r/s + s)`


Find the derivative of f (x) = 3x at x = 2 


Find the derivative of f (x) = x2 − 2 at x = 10


Find the derivative of the following function at the indicated point:


\[\frac{x + 2}{3x + 5}\]


 x2 + x + 3


Differentiate  of the following from first principle:

\[\cos\left( x - \frac{\pi}{8} \right)\]


Differentiate  of the following from first principle:

 x sin x


Differentiate each of the following from first principle:

\[\sqrt{\sin 2x}\] 


Differentiate each of the following from first principle:

\[\frac{\sin x}{x}\]


(2x2 + 1) (3x + 2) 


\[\left( \sqrt{x} + \frac{1}{\sqrt{x}} \right)^3\] 


\[\frac{(x + 5)(2 x^2 - 1)}{x}\]


\[\log\left( \frac{1}{\sqrt{x}} \right) + 5 x^a - 3 a^x + \sqrt[3]{x^2} + 6 \sqrt[4]{x^{- 3}}\] 


\[If y = \sqrt{\frac{x}{a}} + \sqrt{\frac{a}{x}}, \text{ prove that } 2xy\frac{dy}{dx} = \left( \frac{x}{a} - \frac{a}{x} \right)\]  


If for f (x) = λ x2 + μ x + 12, f' (4) = 15 and f' (2) = 11, then find λ and μ. 


x2 ex log x 


x2 sin x log x 


(1 − 2 tan x) (5 + 4 sin x)


logx2 x


x−3 (5 + 3x) 


Differentiate each of the following functions by the product rule and the other method and verify that answer from both the methods is the same.

(3 sec x − 4 cosec x) (−2 sin x + 5 cos x)


(ax + b)n (cx + d)n 


\[\frac{x^2 + 1}{x + 1}\] 


\[\frac{2x - 1}{x^2 + 1}\] 


\[\frac{2^x \cot x}{\sqrt{x}}\] 


\[\frac{a + \sin x}{1 + a \sin x}\] 


\[\frac{a + b \sin x}{c + d \cos x}\] 


\[\frac{\sec x - 1}{\sec x + 1}\] 


If \[\frac{\pi}{2}\] then find \[\frac{d}{dx}\left( \sqrt{\frac{1 + \cos 2x}{2}} \right)\]


Write the value of \[\frac{d}{dx}\left( x \left| x \right| \right)\]


If f (x) = |x| + |x−1|, write the value of \[\frac{d}{dx}\left( f (x) \right)\]


If f (1) = 1, f' (1) = 2, then write the value of \[\lim_{x \to 1} \frac{\sqrt{f (x)} - 1}{\sqrt{x} - 1}\] 


If f (x) =  \[\log_{x_2}\]write the value of f' (x). 


Mark the correct alternative in  of the following:

If\[f\left( x \right) = 1 - x + x^2 - x^3 + . . . - x^{99} + x^{100}\]then \[f'\left( 1 \right)\] 


Mark the correct alternative in of the following:

If \[y = \sqrt{x} + \frac{1}{\sqrt{x}}\] then \[\frac{dy}{dx}\] at x = 1 is


(ax2 + cot x)(p + q cos x)


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×