मराठी

Find the derivative of (5x3 + 3x – 1) (x – 1).

Advertisements
Advertisements

प्रश्न

Find the derivative of (5x3 + 3x – 1) (x – 1).

बेरीज
Advertisements

उत्तर

Let f (x) = (5x3 + 3x – 1) (x – 1)    ...(1)

Differentiating (1) with respect to x, we get

f'(x) = (5x3 + 3x - 1) (x - 1) + (5x3 + 3x - 1)(x - 1)

= f'(x) = (5.3x2 + 3 - 0) (x - 1) + (5x3 + 3x - 1) (1 - 0)

= (15x2 + 3) (x - 1) + (5x3 + 3x -1) (1)

= 15x3 + 3x - 15x2 - 3 + 5x3 + 3x - 1

∴ f'(x) = 20x3 - 15x2 + 6x - 4

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 12: Limits and Derivatives - EXERCISE 12.2 [पृष्ठ २४९]

APPEARS IN

एनसीईआरटी Mathematics [English] Class 11
पाठ 12 Limits and Derivatives
EXERCISE 12.2 | Q 9. (ii) | पृष्ठ २४९

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

Find the derivative of x at x = 1.


Find the derivative of the following function (it is to be understood that a, b, c, d, p, q, r and s are fixed non-zero constants and m and n are integers):

`1/(ax^2 + bx + c)`


Find the derivative of the following function (it is to be understood that a, b, c, d, p, q, r and s are fixed non-zero constants and m and n are integers):

`(px^2 +qx + r)/(ax +b)`


Find the derivative of the following function (it is to be understood that a, b, c, d, p, q, r and s are fixed non-zero constants and m and n are integers):

sin (x + a)


Find the derivative of f (x) = x2 − 2 at x = 10


Find the derivative of the following function at the indicated point:

2 cos x at x =\[\frac{\pi}{2}\] 


\[\frac{x^2 + 1}{x}\]


x ex


Differentiate of the following from first principle:

 x cos x


Differentiate each of the following from first principle:

\[\frac{\sin x}{x}\]


Differentiate each of the following from first principle: 

\[\frac{\cos x}{x}\]


Differentiate each of the following from first principle:

x2 e


tan2 


\[\sqrt{\tan x}\]


\[\text{ If } y = \left( \sin\frac{x}{2} + \cos\frac{x}{2} \right)^2 , \text{ find } \frac{dy}{dx} at x = \frac{\pi}{6} .\]


(x3 + x2 + 1) sin 


sin x cos x


x5 ex + x6 log 


(1 − 2 tan x) (5 + 4 sin x)


logx2 x


x4 (5 sin x − 3 cos x)


(2x2 − 3) sin 


Differentiate in two ways, using product rule and otherwise, the function (1 + 2 tan x) (5 + 4 cos x). Verify that the answers are the same. 


Differentiate each of the following functions by the product rule and the other method and verify that answer from both the methods is the same. 

 (3x2 + 2)2


(ax + b) (a + d)2


\[\frac{x^2 + 1}{x + 1}\] 


\[\frac{a x^2 + bx + c}{p x^2 + qx + r}\] 


\[\frac{1}{a x^2 + bx + c}\] 


\[\frac{x \tan x}{\sec x + \tan x}\]


\[\frac{x}{1 + \tan x}\] 


\[\frac{1}{a x^2 + bx + c}\] 


If f (x) = \[\frac{x^2}{\left| x \right|},\text{ write }\frac{d}{dx}\left( f (x) \right)\] 


If f (1) = 1, f' (1) = 2, then write the value of \[\lim_{x \to 1} \frac{\sqrt{f (x)} - 1}{\sqrt{x} - 1}\] 


Mark the correct alternative in  of the following:

If\[f\left( x \right) = 1 - x + x^2 - x^3 + . . . - x^{99} + x^{100}\]then \[f'\left( 1 \right)\] 


Mark the correct alternative in  of the following: 

If \[y = \frac{1 + \frac{1}{x^2}}{1 - \frac{1}{x^2}}\] then \[\frac{dy}{dx} =\] 


Mark the correct alternative in  of the following:
If \[y = \frac{\sin\left( x + 9 \right)}{\cos x}\] then \[\frac{dy}{dx}\] at x = 0 is 


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×