हिंदी

(Ax + B)N (Cx + D)N

Advertisements
Advertisements

प्रश्न

(ax + b)n (cx d)

Advertisements

उत्तर

\[\left( ax + b \right)^n \left( cx + d \right)^n \]
\[\text{ Let } u = \left( ax + b \right)^n , v = \left( cx + d \right)^n \]
\[\text{ Then }, u' = na \left( ax + b \right)^{n - 1} , v' = nc \left( cx + d \right)^{n - 1} \]
\[\text{ Using the product rule }: \]
\[\frac{d}{dx}\left( uv \right) = uv' + u'v\]
\[\frac{d}{dx}\left[ \left( ax + b \right)^n \left( cx + d \right)^n \right] = \left( ax + b \right)^n \times nc \left( cx + d \right)^{n - 1} + na \left( ax + b \right)^{n - 1} \times \left( cx + d \right)^n \]
\[ = n \left( ax + b \right)^{n - 1} \left( cx + d \right)^{n - 1} \left( acx + cb + acx + ad \right)\]
\[ = n \left( ax + b \right)^{n - 1} \left( cx + d \right)^{n - 1} \left( 2acx + cb + ad \right)\]
\[\]

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 30: Derivatives - Exercise 30.4 [पृष्ठ ३९]

APPEARS IN

आर.डी. शर्मा Mathematics [English] Class 11
अध्याय 30 Derivatives
Exercise 30.4 | Q 28 | पृष्ठ ३९

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

Find the derivative of `2x - 3/4`


Find the derivative of `2/(x + 1) - x^2/(3x -1)`.


Find the derivative of the following function (it is to be understood that a, b, c, d, p, q, r and s are fixed non-zero constants and m and n are integers):

cosec x cot x


Find the derivative of the following function (it is to be understood that a, b, c, d, p, q, r and s are fixed non-zero constants and m and n are integers):

`(sec x - 1)/(sec x + 1)`


Find the derivative of the following function at the indicated point:


\[\frac{2x + 3}{x - 2}\] 


Differentiate each of the following from first principle:

ex


Differentiate  of the following from first principle:

 eax + b


Differentiate  of the following from first principle:

sin (x + 1)


Differentiate each of the following from first principle: 

\[\frac{\cos x}{x}\]


Differentiate each of the following from first principle:

\[\sqrt{\sin (3x + 1)}\]


Differentiate each of the following from first principle: 

\[e^{x^2 + 1}\]


tan2 


\[\cos \sqrt{x}\]


\[\frac{2 x^2 + 3x + 4}{x}\] 


\[\frac{1}{\sin x} + 2^{x + 3} + \frac{4}{\log_x 3}\] 


cos (x + a)


x3 sin 


(x3 + x2 + 1) sin 


\[\frac{2^x \cot x}{\sqrt{x}}\] 


sin2 


(2x2 − 3) sin 


x−3 (5 + 3x


Differentiate in two ways, using product rule and otherwise, the function (1 + 2 tan x) (5 + 4 cos x). Verify that the answers are the same. 


\[\frac{2x - 1}{x^2 + 1}\] 


\[\frac{1}{a x^2 + bx + c}\] 


\[\frac{\sqrt{a} + \sqrt{x}}{\sqrt{a} - \sqrt{x}}\] 


\[\frac{3^x}{x + \tan x}\] 


\[\frac{a + b \sin x}{c + d \cos x}\] 


\[\frac{\sec x - 1}{\sec x + 1}\] 


\[\frac{x}{\sin^n x}\]


Write the value of the derivative of f (x) = |x − 1| + |x − 3| at x = 2.


Mark the correct alternative in of the following: 

If \[f\left( x \right) = \frac{x - 4}{2\sqrt{x}}\]

 


Find the derivative of x2 cosx.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×