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E X Log √ X Tan X - Mathematics

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प्रश्न

\[e^x \log \sqrt{x} \tan x\] 

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उत्तर

\[\text{ Let } u = e^x ; v = \log \sqrt{x}; w = \tan x\]
\[\text{ Then } , u' = e^x ; v' = \frac{1}{\sqrt{x}} \times \frac{1}{2\sqrt{x}} = \frac{1}{2x}; w' = \sec^2 x\]
\[\text{ Using the product rule }:\]
\[\frac{d}{dx}\left( uvw \right) = u'vw + uv'w + uvw'\]
\[ = e^x \log \sqrt{x}\tan x + e^x \times \frac{1}{2x}\tan x + e^x \log \sqrt{x} \sec^2 x\]
\[ = e^x \left( \log x^\frac{1}{2} . \tan x + \frac{\tan x}{2x} + \log x^\frac{1}{2} . \sec^2 x \right)\]
\[ = e^x \left( \frac{1}{2} \log x . \tan x + \frac{\tan x}{2x} + \frac{1}{2} \log x . \sec^2 x \right)\]
\[ = \frac{e^x}{2}\left( \log x . \tan x + \frac{\tan x}{x} + \log x . \sec^2 x \right)\]

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अध्याय 30: Derivatives - Exercise 30.4 [पृष्ठ ३९]

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आरडी शर्मा Mathematics [English] Class 11
अध्याय 30 Derivatives
Exercise 30.4 | Q 17 | पृष्ठ ३९

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