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( X + 1 X ) ( √ X + 1 √ X ) - Mathematics

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प्रश्न

\[\left( x + \frac{1}{x} \right)\left( \sqrt{x} + \frac{1}{\sqrt{x}} \right)\] 

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उत्तर

\[\frac{d}{dx}\left[ \left( x + \frac{1}{x} \right)\left( \sqrt{x} + \frac{1}{\sqrt{x}} \right) \right]\]
\[ = \frac{d}{dx}\left[ \left( x + x^{- 1} \right)\left( x^\frac{1}{2} + x^\frac{- 1}{2} \right) \right]\]
\[ = \frac{d}{dx}\left( x^\frac{3}{2} + x^\frac{1}{2} + x^\frac{- 1}{2} + x^\frac{- 3}{2} \right)\]
\[ = \frac{d}{dx}\left( x^\frac{3}{2} \right) + \frac{d}{dx}\left( x^\frac{1}{2} \right) + \frac{d}{dx}\left( x^\frac{- 1}{2} \right) + \frac{d}{dx}\left( x^\frac{- 3}{2} \right)\]
\[ = \frac{3}{2} x^\frac{1}{2} + \frac{1}{2} x^\frac{- 1}{2} - \frac{1}{2} x^\frac{- 3}{2} - \frac{3}{2} x^\frac{- 5}{2} \]

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अध्याय 30: Derivatives - Exercise 30.3 [पृष्ठ ३४]

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आरडी शर्मा Mathematics [English] Class 11
अध्याय 30 Derivatives
Exercise 30.3 | Q 7 | पृष्ठ ३४

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