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Log3 x + 3 loge x + 2 tan x

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प्रश्न

 log3 x + 3 loge x + 2 tan x

योग
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उत्तर

\[\frac{d}{dx}\left( \log_3 x + 3 \log_e x + 2 \tan x \right)\]

\[ = \frac{d}{dx}\left( \frac{\log x}{\log 3} \right) + 3\frac{d}{dx}\left( \log_e x \right) + 2\frac{d}{dx}\left( \tan x \right)\]

\[ = \frac{1}{\log 3} . \frac{1}{x} + 3 . \frac{1}{x} + 2 \sec^2 x\]

\[ = \frac{1}{x \log 3} + \frac{3}{x} + 2 \sec^2 x\]

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अध्याय 30: Derivatives - Exercise 30.3 [पृष्ठ ३३]

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आर.डी. शर्मा Mathematics [English] Class 11
अध्याय 30 Derivatives
Exercise 30.3 | Q 6 | पृष्ठ ३३

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