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प्रश्न
ex log a + ea long x + ea log a
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उत्तर
\[\frac{d}{dx}\left( e^{x \log a} + e^{a \log x} + e^{a \log a} \right)\]
\[ = \frac{d}{dx}\left( e^{x \log a} \right) + \frac{d}{dx}\left( e^{a \log x} \right) + \frac{d}{dx}\left( e^{a \log a} \right)\]
`= \frac{d}{dx}\left( e^\log a^x \right) + \frac{d}{dx}\left( {e^\log x}^a \right) + \frac{d}{dx}\left( e^\log a^a \right)`
`= \frac{d}{dx}\left( a^x \right) + \frac{d}{dx}\left( x^a \right) + \frac{d}{dx}\left( a^a \right)`
\[ = a^x \log a + a x^{a - 1} + 0 \]
\[ = a^x \log a + a x^{a - 1}\]
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