Advertisements
Advertisements
प्रश्न
Find the measure of all the angles of a parallelogram, if one angle is 24° less than twice the smallest angle
Advertisements
उत्तर
Let the smallest angle be x
Then, the other angle is (3x - 24)
Now, x + 2x - 24 =180°
3x - 24 = 180°
⇒ 3x = 180 + 24
⇒ 3x = 204°
⇒ x = `204/3` = 68°
⇒ x = 68°
⇒ 2x - 24° = 2´68° - 24° =136° - 24° =112°
Hence four angles are 68°,112°, 68°,112°.
APPEARS IN
संबंधित प्रश्न
Find the angle measure x in the given Figure
Find the angle measure x in the given Figure
Find x + y + z + w
In a quadrilateral ABCD, the angles A, B, C and D are in the ratio 1 : 2 : 4 : 5. Find the measure of each angles of the quadrilateral
The angles of a quadrilateral are in the ratio 3 : 5 : 9 : 13 Find all the angles of the quadrilateral.
ABCD is a parallelogram in which ∠A = 70°. Compute ∠B, ∠C and ∠D .
Can all the angles of a quadrilateral be right angles? Give reason for your answer.
In the following figure, P is the mid-point of side BC of a parallelogram ABCD such that ∠BAP = ∠DAP. Prove that AD = 2CD.
If three angles of a quadrilateral are each equal to 75°, the fourth angle is ______.
Sum of all the angles of a quadrilateral is 180°.
