Advertisements
Advertisements
प्रश्न
Find the measure of all the angles of a parallelogram, if one angle is 24° less than twice the smallest angle
Advertisements
उत्तर
Let the smallest angle be x
Then, the other angle is (3x - 24)
Now, x + 2x - 24 =180°
3x - 24 = 180°
⇒ 3x = 180 + 24
⇒ 3x = 204°
⇒ x = `204/3` = 68°
⇒ x = 68°
⇒ 2x - 24° = 2´68° - 24° =136° - 24° =112°
Hence four angles are 68°,112°, 68°,112°.
APPEARS IN
संबंधित प्रश्न
Find the angle measure x in the given Figure
Find the angle measure x in the given Figure
Find x + y + z
ABCD is a parallelogram in which ∠A = 70°. Compute ∠B, ∠C and ∠D .
In Fig. below, ABCD is a parallelogram in which ∠DAB = 75° and ∠DBC = 60°. Compute
∠CDB and ∠ADB.
In a rhombus ABCD, if ∠ACB = 40°, then ∠ADB =
Can all the four angles of a quadrilateral be obtuse angles? Give reason for your answer.
Can all the angles of a quadrilateral be right angles? Give reason for your answer.
If three angles of a quadrilateral are each equal to 75°, the fourth angle is ______.
Sum of all the angles of a quadrilateral is 180°.
