Advertisements
Advertisements
प्रश्न
In a quadrilateral ABCD, the angles A, B, C and D are in the ratio 1 : 2 : 4 : 5. Find the measure of each angles of the quadrilateral
Advertisements
उत्तर
Let the angles of the quadrilateral be
A = x, B = 2x, C = 4x and D = 5x then,
A + B + C + D = 360°
⇒ x + 2x + 4x + 5x = 360°
⇒ 12x = 360°
⇒ x = `(360°)/12`
⇒ x = 30°
∴ A = x = 30°
B = 2x = 60°
C = 4x = 30° (4) = 120°
D = 5x = 5 (30°) = 150°
APPEARS IN
संबंधित प्रश्न
In a quadrilateral ABCD, CO and DO are the bisectors of `∠`C and ∠D respectively. Prove that
`∠`COD = `1/2` (`∠`A+ `∠`B).
ABCD is a parallelogram in which ∠A = 70°. Compute ∠B, ∠C and ∠D .
In Fig. below, ABCD is a parallelogram in which ∠DAB = 75° and ∠DBC = 60°. Compute
∠CDB and ∠ADB.

If an angle of a parallelogram is two-third of its adjacent angle, the smallest angle of the parallelogram is
If the degree measures of the angles of quadrilateral are 4x, 7x, 9x and 10x, what is the sum of the measures of the smallest angle and largest angle?
Can the angles 110º, 80º, 70º and 95º be the angles of a quadrilateral? Why or why not?
One angle of a quadrilateral is of 108º and the remaining three angles are equal. Find each of the three equal angles.
The angle between two altitudes of a parallelogram through the vertex of an obtuse angle of the parallelogram is 60º. Find the angles of the parallelogram.
The angles P, Q, R and S of a quadrilateral are in the ratio 1:3:7:9. Then PQRS is a ______.
Sum of all the angles of a quadrilateral is 180°.
