Advertisements
Advertisements
प्रश्न
In a quadrilateral ABCD, the angles A, B, C and D are in the ratio 1 : 2 : 4 : 5. Find the measure of each angles of the quadrilateral
Advertisements
उत्तर
Let the angles of the quadrilateral be
A = x, B = 2x, C = 4x and D = 5x then,
A + B + C + D = 360°
⇒ x + 2x + 4x + 5x = 360°
⇒ 12x = 360°
⇒ x = `(360°)/12`
⇒ x = 30°
∴ A = x = 30°
B = 2x = 60°
C = 4x = 30° (4) = 120°
D = 5x = 5 (30°) = 150°
APPEARS IN
संबंधित प्रश्न

Find x + y + z + w
In a quadrilateral ABCD, CO and DO are the bisectors of `∠`C and ∠D respectively. Prove that
`∠`COD = `1/2` (`∠`A+ `∠`B).
Two opposite angles of a parallelogram are (3x – 2)° and (50 – x)°. Find the measure of each angle of the parallelogram .
In Fig. below, ABCD is a parallelogram in which ∠DAB = 75° and ∠DBC = 60°. Compute
∠CDB and ∠ADB.

If the angles of a quadrilateral are in the ratio 3 : 5 : 9 : 13, then find the measure of the smallest angle.
In the given figure, PQRS is a rhombus in which the diagonal PR is produced to T. If ∠SRT = 152°, find x, y and z.

The two diagonals are equal in a
The figure formed by joining the mid-points of the adjacent sides of a square is a
Can all the angles of a quadrilateral be acute angles? Give reason for your answer.
Sum of all the angles of a quadrilateral is 180°.
