Advertisements
Advertisements
प्रश्न
Two opposite angles of a parallelogram are (3x – 2)° and (50 – x)°. Find the measure of each angle of the parallelogram .
Advertisements
उत्तर
We know that
Opposite sides of a parallelogram are equal
∴ 3x - 2 = 50 - x
⇒ 3x + x = 50 + 2
⇒ 4x = 52
⇒ x = 13°
∴(3x - 2)° = (3 × 13 - 2) = 37°
(50 - x)° = (50 -13°) = 37°
Adjacent angles of a parallelogram are supplementary
∴ x + 37 = 180°
∴ x = 180° - 37° = 143°
Hence, four angles are : 37°,143°, 37°,143°
APPEARS IN
संबंधित प्रश्न
Find the angle measure x in the given Figure
Find x + y + z
In a quadrilateral ABCD, CO and DO are the bisectors of `∠`C and ∠D respectively. Prove that
`∠`COD = `1/2` (`∠`A+ `∠`B).
In Fig. below, ABCD is a parallelogram in which ∠DAB = 75° and ∠DBC = 60°. Compute
∠CDB and ∠ADB.
If the angles of a quadrilateral are in the ratio 3 : 5 : 9 : 13, then find the measure of the smallest angle.
Diagonals necessarily bisect opposite angles in a
All the angles of a quadrilateral are equal. What special name is given to this quadrilateral?
The angle between two altitudes of a parallelogram through the vertex of an obtuse angle of the parallelogram is 60º. Find the angles of the parallelogram.
Which of the following can be four interior angles of a quadrilateral?
The angles P, Q, R and S of a quadrilateral are in the ratio 1:3:7:9. Then PQRS is a ______.
