Question

Find the measure of all the angles of a parallelogram, if one angle is 24° less than twice the smallest angle

Answer 1

Let the smallest angle be x

Then, the other angle is (3x - 24)

Now, x + 2x - 24 =180°

3x - 24 = 180°

⇒ 3x = 180 + 24

⇒ 3x = 204°

⇒ x = `204/3` = 68°

⇒ x = 68°

⇒ 2x - 24° = 2´68° - 24° =136° - 24° =112°

Hence four angles are 68°,112°, 68°,112°.