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प्रश्न
Find the measure of all the angles of a parallelogram, if one angle is 24° less than twice the smallest angle
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उत्तर
Let the smallest angle be x
Then, the other angle is (3x - 24)
Now, x + 2x - 24 =180°
3x - 24 = 180°
⇒ 3x = 180 + 24
⇒ 3x = 204°
⇒ x = `204/3` = 68°
⇒ x = 68°
⇒ 2x - 24° = 2´68° - 24° =136° - 24° =112°
Hence four angles are 68°,112°, 68°,112°.
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