Advertisements
Advertisements
प्रश्न
Find the measure of all the angles of a parallelogram, if one angle is 24° less than twice the smallest angle
Advertisements
उत्तर
Let the smallest angle be x
Then, the other angle is (3x - 24)
Now, x + 2x - 24 =180°
3x - 24 = 180°
⇒ 3x = 180 + 24
⇒ 3x = 204°
⇒ x = `204/3` = 68°
⇒ x = 68°
⇒ 2x - 24° = 2´68° - 24° =136° - 24° =112°
Hence four angles are 68°,112°, 68°,112°.
APPEARS IN
संबंधित प्रश्न
Three angles of a quadrilateral are respectively equal to 110°, 50° and 40°. Find its fourth angle
In a quadrilateral ABCD, CO and DO are the bisectors of `∠`C and ∠D respectively. Prove that
`∠`COD = `1/2` (`∠`A+ `∠`B).
ABCD is a parallelogram in which ∠A = 70°. Compute ∠B, ∠C and ∠D .
The diagonals of a rectangle ABCD meet at O, If ∠BOC = 44°, find ∠OAD.
All the angles of a quadrilateral are equal. What special name is given to this quadrilateral?
Can all the four angles of a quadrilateral be obtuse angles? Give reason for your answer.
A quadrilateral has three acute angles. If each measures 80°, then the measure of the fourth angle is ______.
Which of the following can be four interior angles of a quadrilateral?
The angles P, Q, R and S of a quadrilateral are in the ratio 1:3:7:9. Then PQRS is a ______.
The polygon in which sum of all exterior angles is equal to the sum of interior angles is called ______.
