Advertisements
Advertisements
प्रश्न
In Fig. below, ABCD is a parallelogram in which ∠DAB = 75° and ∠DBC = 60°. Compute
∠CDB and ∠ADB.
Advertisements
उत्तर
To find `∠`CDB and `∠`ADB
`∠`CBD = `∠`ABD = 60° [Alternative interior angle AD || BC and BD is the transversal]
In a parallelogram ABCD
`∠`A = `∠`C = 75° [ ∵ Opposite side angles of a parallelogram are equal]
In `∠`BDC
`∠`CBD + `∠`C + `∠`CDB =180° [Angle sum property]
⇒ 60° + 75° + `∠`CDB = 180°
⇒`∠`CDB = 180° - (60° + 75°)
⇒ `∠`CDB = 45°
Hence `∠`CDB = 45°, `∠`ADB = 60°
APPEARS IN
संबंधित प्रश्न
Find the angle measure x in the given Figure
Find x + y + z
In a quadrilateral ABCD, the angles A, B, C and D are in the ratio 1 : 2 : 4 : 5. Find the measure of each angles of the quadrilateral
In a quadrilateral ABCD, bisectors of angles A and B intersect at O such that ∠AOB = 75°, then write the value of ∠C + ∠D.
The two diagonals are equal in a
The diagonals AC and BD of a rectangle ABCD intersect each other at P. If ∠ABD = 50°, then ∠DPC =
Can the angles 110º, 80º, 70º and 95º be the angles of a quadrilateral? Why or why not?
Can all the angles of a quadrilateral be acute angles? Give reason for your answer.
Can all the angles of a quadrilateral be right angles? Give reason for your answer.
In a quadrilateral PQRS, ∠P = 50°, ∠Q = 50°, ∠R = 60°. Find ∠S. Is this quadrilateral convex or concave?
