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Find |(1+i)(2+i)(3+i)|.

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प्रश्न

Find `|(1 + i) ((2 + i))/((3 + i))|`.

योग
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उत्तर

`|(1 + i) ((2 + i))/((3 + i)) xx (3 - i)/(3 - i)|`

= `|(1 + i) . (6 - 2i + 3i - i^2)/(9 - i^2)|`

= `|((1 + i).(7 + i))/(9 + 1)|`

= `|(7 + i + 7i + i^2)/10|`

= `|(7 + 8i - 1)/10|`

= `|(6 + 8i)/10|`

= `|3/5 + 4/5 i|`

= `sqrt((3/5)^2 + (4/5)^2)`

= 1

Hence, `|(1 + i) ((2 + i)/(3 + i))|` = 1.

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अध्याय 5: Complex Numbers and Quadratic Equations - Exercise [पृष्ठ ९५]

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एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 11
अध्याय 5 Complex Numbers and Quadratic Equations
Exercise | Q 32 | पृष्ठ ९५

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