Advertisements
Advertisements
प्रश्न
factorise: a2 - 23a -108
योग
Advertisements
उत्तर
a2 - 23a -108
= a2 - 27a + 4a - 108 ...[27 × 4 = 108 and 27 -4 = 23]
= a(a - 27) + 4(a - 27)
= (a - 27)(a + 4)
shaalaa.com
Factorisation by Grouping
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Factorise by the grouping method : (ax + by)2 + (bx - ay)2
Factorise : a2 - ab - ca + bc
Factorise : a3 -a2 +a -1
Factorise : - x2y - x + 3xy + 3
Factorise : 3a2b - 12a2 - 9b + 36
Factorise : ab2 - (a - c) b - c
Factorise : (a2 − b2) c + (b2 − c2)a
factorise: 4c2 + 3c - 10
Factorise the following by grouping the terms:
x(x - 4)- x + 4
Factorise the following by grouping the terms:
9x3 + 6x2y2 - 4y3 - 6xy
