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प्रश्न
factorise:
9a (x − 2y)4 − 12a (x − 2y)3
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उत्तर
9a (x − 2y)4 − 12a (x − 2y)3
The common factors between the terms are:
- a,
- (x − 2y)3, (the lower power of (x−2y),
- And the coefficients 9 and 12 have a common factor of 3.
Factor out 3a(x − 2y)3:
9a(x − 2y)4 − 12a(x − 2y)3 = 3a(x − 2y)3 (3(x − 2y) −4)
Simplify 3(x − 2y) −4:
3(x − 2y) −4 = 3x − 6y − 4
Thus, the expression becomes:
3a(x − 2y)3 (3x − 6y − 4)
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