Advertisements
Advertisements
प्रश्न
Find the common factors of the terms.
14pq, 28p2q2
योग
Advertisements
उत्तर
The given terms are 14pq and 28p2q2
14pq = 2 × 7 × p × q
28p2q2 = 2 × 2 × 7 × p × p × q × q
The common factors are 2 × 7 × p × q.
And, 2 × 7 × p × q
= 14pq
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 12: Factorisation - EXERCISE 12.1 [पृष्ठ १४८]
APPEARS IN
संबंधित प्रश्न
Find the common factors of the terms.
16x3, −4x2, 32x
Factorise the following expression:
7a2 + 14a
Factorize the following:
20a12b2 − 15a8b4
Factorise : `x^2 + [a^2 + 1]/a x + 1`
Factorise : 3 - 5x + 5y - 12(x - y)2
factorise : xy2 + (x - 1) y - 1
Factorise the following by taking out the common factors:
2x5y + 8x3y2 - 12x2y3
Factorise the following by taking out the common factors:
(a - b)2 -2(a - b)
Factorise:
`y^2 + (1)/(4y^2) + 1 - 6y - (3)/y`
Factorise:
5x2 - y2 - 4xy + 3x - 3y
