Advertisements
Advertisements
प्रश्न
Factorise the following expression:
x2yz + xy2z + xyz2
योग
Advertisements
उत्तर
x2yz = x × x × y × z
xy2z = x × y × y × z
xyz2 = x × y × z × z
The common factors are x, y, and z.
∴ x2yz + xy2z + xyz2
= (x × x × y × z) + (x × y × y × z) + (x × y × z × z)
= x × y × z [x + y + z]
= xyz (x + y + z)
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 12: Factorisation - EXERCISE 12.1 [पृष्ठ १४८]
APPEARS IN
संबंधित प्रश्न
Factorise the following expression:
7a2 + 14a
Factorise the following expression:
−16z + 20z3
Factorise the following expression:
− 4a2 + 4ab − 4 ca
Factorise.
15xy − 6x + 5y − 2
Factorize the following:
20a12b2 − 15a8b4
Factorize the following:
ax2y + bxy2 + cxyz
Find the value of : `[(6.7)^2 - (3.3)^2]/[6.7 - 3.3]`
Factorise : 4a2 - 8ab
Factorise the following by taking out the common factors:
24m4n6 + 56m6n4 - 72m2n2
Factorise 10x2 - 18x3+ 14x4
