Advertisements
Advertisements
प्रश्न
Factorise the following expression:
x2yz + xy2z + xyz2
योग
Advertisements
उत्तर
x2yz = x × x × y × z
xy2z = x × y × y × z
xyz2 = x × y × z × z
The common factors are x, y, and z.
∴ x2yz + xy2z + xyz2
= (x × x × y × z) + (x × y × y × z) + (x × y × z × z)
= x × y × z [x + y + z]
= xyz (x + y + z)
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 12: Factorisation - EXERCISE 12.1 [पृष्ठ १४८]
APPEARS IN
संबंधित प्रश्न
Find the common factors of the terms.
10pq, 20qr, 30rp
Factorise the following expression:
20 l2m + 30 alm
Factorize the following:
2a4b4 − 3a3b5 + 4a2b5
Factorise : 3 - 5x + 5y - 12(x - y)2
Factorise : 15x + 5
Factorise : 2x3b2 - 4x5b4
factorise : 6x3 - 8x2
Factorise the following by taking out the common factors:
24m4n6 + 56m6n4 - 72m2n2
Factorise:
`y^2 + (1)/(4y^2) + 1 - 6y - (3)/y`
Factorise 10x2 - 18x3+ 14x4
