Advertisements
Advertisements
प्रश्न
Factorise:
`4"a"^2 + (1)/(4"a"^2) - 2 - 6"a" + (3)/(2"a")`
Advertisements
उत्तर
`4"a"^2 + (1)/(4"a"^2) - 2 - 6"a" + (3)/(2"a")`
= `(4"a"^2 + 1/(4"a"^2) - 2) - (6"a" - 3/(2"a"))`
= `(2"a" - 1/(2"a"))^2 - 3(2"a" - 1/(2"a"))`
= `(2"a" - 1/(2"a")) (2"a" - 1/(2"a") - 3)`
APPEARS IN
संबंधित प्रश्न
Find the common factors of the terms.
2x, 3x2, 4
Factorise the following expression:
10a2 − 15b2 + 20c2
Factorise the following expression:
ax2y + bxy2 + cxyz
Factorise.
x2 + xy + 8x + 8y
Factorise.
15xy − 6x + 5y − 2
Factories by taking out common factors :
xy(3x2 - 2y2) - yz(2y2 - 3x2) + zx(15x2 - 10y2)
Factorise : `x^2 + [a^2 + 1]/a x + 1`
Factorise : (a2 - 3a) (a2 - 3a + 7) + 10
Factorise : 9x 2 + 3x - 8y - 64y2
Factorise : `1/4 ( a + b )^2 - 9/16 ( 2a - b )^2`
Factorise : 2(ab + cd) - a2 - b2 + c2 + d2
Factorise : 15x + 5
Factorise : 4a2 - 8ab
Factorise : 15x4y3 - 20x3y
Factorise : 17a6b8 - 34a4b6 + 51a2b4
Factorise : 3x5y - 27x4y2 + 12x3y3
factorise : 6x3 - 8x2
Factorise: 36x2y2 - 30x3y3 + 48x3y2
factorise : a2 - ab - 3a + 3b
Factorise:
a2 – ab(1 – b) – b3
factorise : xy2 + (x - 1) y - 1
factorise : ab(x2 + y2) - xy (a2 + b2)
Factorise: a2 - 0·36 b2
Factorise the following by taking out the common factors:
24m4n6 + 56m6n4 - 72m2n2
Factorise the following by taking out the common factors:
36(x + y)3 - 54(x + y)2
Factorise:
`y^2 + (1)/(4y^2) + 1 - 6y - (3)/y`
Factorise the following by taking out the common factor
9x5y3 + 6x3y2 – 18x2y
