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प्रश्न
Factorise the following by taking out the common factors:
36(x + y)3 - 54(x + y)2
योग
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उत्तर
36(x + y)3 - 54(x + y)2
Here, the common factor is 18(x + y)2.
Dividing throughout by 18(x + y)2, we get
`(36(x + y)^3)/(18(x + y)^2) - (54(x + y)^2)/(18(x + y)^2)`
= 2(x + y) - 3
∴ 36(x + y)3 - 54(x + y)2
= 18(x + y)2[2(x + y) - 3].
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