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Factorise the Following by Taking Out the Common Factors: 36(X + Y)3 - 54(X + Y)2

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प्रश्न

Factorise the following by taking out the common factors:
36(x + y)3 - 54(x + y)2

योग
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उत्तर

36(x + y)3 - 54(x + y)
Here, the common factor is 18(x + y)2.
Dividing throughout by 18(x + y)2, we get

`(36(x + y)^3)/(18(x + y)^2) - (54(x + y)^2)/(18(x + y)^2)`
= 2(x + y) - 3
∴ 36(x + y)3 - 54(x + y)2
= 18(x + y)2[2(x + y) - 3].

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अध्याय 5: Factorisation - Exercise 5.1

APPEARS IN

फ्रैंक Mathematics [English] Class 9 ICSE
अध्याय 5 Factorisation
Exercise 5.1 | Q 1.1

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