Advertisements
Advertisements
प्रश्न
factorise : xy2 + (x - 1) y - 1
Advertisements
उत्तर
xy2 + (x - 1) y - 1 = xy2+ xy - y - 1
= xy (y + 1) - 1 (y + 1)
= (xy - 1)(y + 1)
APPEARS IN
संबंधित प्रश्न
Find the common factors of the terms.
3x2y3, 10x3y2, 6x2y2z
Factorise the following expression:
7a2 + 14a
Factorise the following expression:
20 l2m + 30 alm
Factorize the following:
10m3n2 + 15m4n − 20m2n3
Factorize the following:
x2yz + xy2z + xyz2
Factories by taking out common factors :
xy(3x2 - 2y2) - yz(2y2 - 3x2) + zx(15x2 - 10y2)
Factorise:
`x^2 + [a^2 + 1]/a x + 1`
Factorise : (a2 - 3a) (a2 - 3a + 7) + 10
Factorise : 4(2x - 3y)2 - 8x+12y - 3
Factorise : 3x2 + 6x3
Factorise : 6x2y + 9xy2 + 4y3
Factorise : (x + y)(a + b) + (x - y)(a + b)
factorise:
9a (x − 2y)4 − 12a (x − 2y)3
Factorise the following by taking out the common factors:
4x2y3 - 6x3y2 - 12xy2
Factorise the following by taking out the common factors:
5a(x2 - y2) + 35b(x2 - y2)
Factorise the following by taking out the common factors:
(a - b)2 -2(a - b)
Factorise the following by taking out the common factors:
(mx + ny)2 + (nx - my)2
Factorise the following by taking out the common factors:
36(x + y)3 - 54(x + y)2
Factorise:
`"p"^2 + (1)/"p"^2 - 3`
Factorise the following by taking out the common factor
9x5y3 + 6x3y2 – 18x2y
