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प्रश्न
Factorise the following expression:
−16z + 20z3
योग
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उत्तर
16z = −1 × 2 × 2 × 2 × 2 × z
20z3 = 2 × 2 × 5 × z × z × z
The common factors are 2, 2, and z.
∴ −16z + 20z3 = −1 (2 × 2 × 2 × 2 × z) + (2 × 2 × 5 × z × z × z)
= (2 × 2 × z) [−1 (2 × 2) + (5 × z × z)]
= 4z (− 4 + 5z2)
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अध्याय 12: Factorisation - EXERCISE 12.1 [पृष्ठ १४८]
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