हिंदी

Express the Following Complex Number in the Standard Form a + I B: ( 1 + I ) ( 1 + √ 3 I ) 1 − I .

Advertisements
Advertisements

प्रश्न

Express the following complex number in the standard form a + i b:

\[\frac{(1 + i)(1 + \sqrt{3}i)}{1 - i}\] .

Advertisements

उत्तर

\[\frac{\left( 1 + i \right)\left( 1 + \sqrt{3i} \right)}{1 - i}\]

\[ = \frac{\left( 1 + i \right)\left( 1 + \sqrt{3i} \right)}{1 - i} \times \frac{1 + i}{1 + i}\]

\[ = \frac{\left( 1 + \sqrt{3}i \right)\left( 1 + i^2 + 2i \right)}{1 - i^2} \left( \because i^2 = - 1 \right)\]

\[ = \frac{\left( 1 + \sqrt{3}i \right)2i}{2}\]

\[ = i\left( 1 + \sqrt{3}i \right)\]

\[ = i + \sqrt{3} i^2 \]

\[ = - \sqrt{3} + i\]

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 13: Complex Numbers - Exercise 13.2 [पृष्ठ ३१]

APPEARS IN

आर.डी. शर्मा Mathematics [English] Class 11
अध्याय 13 Complex Numbers
Exercise 13.2 | Q 1.06 | पृष्ठ ३१

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

Express the given complex number in the form a + ib: i9 + i19


Express the given complex number in the form a + ib: `(1/5 + i 2/5) - (4 + i 5/2)`


Express the given complex number in the form a + ib:

`[(1/3 + i 7/3) + (4 + i 1/3)] -(-4/3 + i)`


Let z1 = 2 – i, z2 = –2 + i. Find `"Im"(1/(z_1barz_1))`


Evaluate the following:

\[( i^{77} + i^{70} + i^{87} + i^{414} )^3\]


Evaluate the following:

\[i^{49} + i^{68} + i^{89} + i^{110}\]


Find the value of the following expression:

\[\frac{i^{592} + i^{590} + i^{588} + i^{586} + i^{584}}{i^{582} + i^{580} + i^{578} + i^{576} + i^{574}}\]


Find the real value of x and y, if

\[(x + iy)(2 - 3i) = 4 + i\]


Find the real value of x and y, if `((1+i)x-2i)/(3+i) + ((2-3i)y+i)/(3-i) = i, xy ∈ R, i = sqrt-1`


Evaluate the following:

\[x^4 + 4 x^3 + 6 x^2 + 4x + 9, \text { when } x = - 1 + i\sqrt{2}\]


Solve the system of equations \[\text { Re }\left( z^2 \right) = 0, \left| z \right| = 2\].


If \[\left| z + 1 \right| = z + 2\left( 1 + i \right)\],find z.


Express the following complex in the form r(cos θ + i sin θ):
1 + i tan α


Express the following complex in the form r(cos θ + i sin θ):

\[\frac{1 - i}{\cos\frac{\pi}{3} + i\sin\frac{\pi}{3}}\]


Express \[\sin\frac{\pi}{5} + i\left( 1 - \cos\frac{\pi}{5} \right)\] in polar form.


If n is any positive integer, write the value of \[\frac{i^{4n + 1} - i^{4n - 1}}{2}\].


Write the argument of −i.


If \[\frac{\left( a^2 + 1 \right)^2}{2a - i} = x + iy\] find the value of  \[x^2 + y^2\].


The polar form of (i25)3 is


The principal value of the amplitude of (1 + i) is


The argument of \[\frac{1 - i\sqrt{3}}{1 + i\sqrt{3}}\] is


If \[z = \frac{1 + 2i}{1 - (1 - i )^2}\], then arg (z) equal


\[\text { If } z = \frac{1}{(2 + 3i )^2}, \text { than } \left| z \right| =\]


If \[z = a + ib\]  lies in third quadrant, then \[\frac{\bar{z}}{z}\] also lies in third quadrant if


If \[f\left( z \right) = \frac{7 - z}{1 - z^2}\] , where \[z = 1 + 2i\] then \[\left| f\left( z \right) \right|\] is


If z is a complex number, then


Simplify : `4sqrt(-4) + 5sqrt(-9) - 3sqrt(-16)`


Find a and b if (a+b) (2 + i) = b + 1 + (10 + 2a)i


Find a and b if abi = 3a − b + 12i


Find a and b if `1/("a" + "ib")` = 3 – 2i


Find a and b if (a + ib) (1 + i) = 2 + i


Evaluate the following : i93  


If `((1 - i)/(1 + i))^100` = a + ib, then find (a, b).


State True or False for the following:

The order relation is defined on the set of complex numbers.


Match the statements of Column A and Column B.

Column A Column B
(a) The polar form of `i + sqrt(3)` is  (i) Perpendicular bisector of
segment joining (–2, 0)
and (2, 0).
(b) The amplitude of `-1 + sqrt(-3)` is  (ii) On or outside the circle
having centre at (0, –4)
and radius 3.
(c) If |z + 2| = |z − 2|, then locus of z is (iii) `(2pi)/3`
(d) If |z + 2i| = |z − 2i|, then locus of z is (iv) Perpendicular bisector of
segment joining (0, –2) and (0, 2).
(e) Region represented by |z + 4i| ≥ 3 is  (v) `2(cos  pi/6 + i sin  pi/6)`
(f) Region represented by |z + 4| ≤ 3 is  (vi) On or inside the circle having
centre (–4, 0) and radius 3 units.
(g) Conjugate of `(1 + 2i)/(1 - i)` lies in (vii) First quadrant
(h) Reciprocal of 1 – i lies in (viii) Third quadrant

Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×