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Explain what would happen if the capacitor given in previous question a 3 mm thick mica sheet (of dielectric constant = 6) were inserted between the plates,

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प्रश्न

Explain what would happen if the capacitor given in previous question a 3 mm thick mica sheet (of dielectric constant = 6) were inserted between the plates,

  1. While the voltage supply remained connected.
  2. After the supply was disconnected.
संख्यात्मक
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उत्तर

(a) Dielectric constant of the mica sheet, k = 6

Initial capacitance, C = 1.77 × 10−11 F

New Capacitance, C' = kC

= 6 × 1.77 × 10−11

= 106 pF

Supply voltage, V = 100 V

New Capacitance, q' = C'V

= 106 × 100 pC

= 1.06 × 10−8 C
Potential across the plates remains 100 V.

(b) Dielectric constant, k = 6

Initial capacitance, C = 1.77 × 10−11 F

New Capacitance, C' = kC

= 6 × 1.77 × 10−11

= 106 pF

If the supply voltage is removed, then there will be no effect on the amount of charge in the plates.

Charge = 1.77 × 10−9 C

Potential across the plates comes from,

∴ `V' = q/(C')`

= `(1.77 xx 10^-9)/(106 xx 10^-12)`

= 16.7 V

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अध्याय 2: Electrostatic Potential and Capacitance - EXERCISES [पृष्ठ ८०]

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एनसीईआरटी Physics Part I and II [English] Class 12
अध्याय 2 Electrostatic Potential and Capacitance
EXERCISES | Q 2.9 | पृष्ठ ८०
एनसीईआरटी Physics Part I and II [English] Class 12
अध्याय 2 Electrostatic Potential and Capacitance
Exercise | Q 2.9 | पृष्ठ ८७

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