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प्रश्न

` ∫   e^{m   sin ^-1  x}/ \sqrt{1-x^2}  ` dx

 

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उत्तर

` ∫   e^{m   sin ^-1  x}/ \sqrt{1-x^2}  ` dx

 


\[\text{Let} \sin^{- 1} x = t\]
\[ \Rightarrow \frac{1}{\sqrt{1 - x^2}}dx = dt\]
Now,` ∫   e^{m   sin ^-1  x}/ \sqrt{1-x^2}  ` dx

\[ = \int e^\text{m t} \cdot dt\]
\[ = \frac{e^{mt}}{m} + C\]

` ∫   e^{m   sin ^-1  x}/m }  ` dx

 

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अध्याय 19: Indefinite Integrals - Exercise 19.09 [पृष्ठ ५९]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 19 Indefinite Integrals
Exercise 19.09 | Q 50 | पृष्ठ ५९

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