Advertisements
Advertisements
प्रश्न
Draw a rhombus, having each side of length 3.5 cm and one of the angles as 40°.
Advertisements
उत्तर
1. Draw a line segment AB of 3.5 cm.
2. Draw \[\angle\] BAX equal to 40\[°\]
3. With A as centre and the radius equal to AB, cut AD at 3.5 cm.
4. With D as centre, cut an arc of radius 3.5 cm.
5. With B as centre, cut an arc of radius 3.5 cm. This arc cuts the arc of step 4 at C.
6. Join DC and BC.
संबंधित प्रश्न
All rhombuses are parallelograms.
Can the following figure be parallelogram. Justify your answer.
Two adjacent angles of a parallelogram are as 1 : 2. Find the measures of all the angles of the parallelogram.
In the following Figure ABCD is a arallelogram, CE bisects ∠C and AF bisects ∠A. In each of the following, if the statement is true, give a reason for the same:
(i) ∠A = ∠C
(ii) \[\angle FAB = \frac{1}{2}\angle A\]
(iii) \[\angle DCE = \frac{1}{2}\angle C\]
(iv) \[\angle CEB = \angle FAB\]
(v) CE || AF
Which of the following statement is true for a rhombus?
Two of its angles are at right angles
Fill in the blank, inthe following, so as to make the statement true:
A square is a rhombus in which .....
ABCD is a rhombus whose diagonals intersect at O. If AB = 10 cm, diagonal BD = 16 cm, find the length of diagonal AC.
State with reason whether the following statement is ‘true’ or ‘false’.
Every parallelogram is a rhombus.
ABCD is a rhombus such that the perpendicular bisector of AB passes through D. Find the angles of the rhombus.
Hint: Join BD. Then ∆ABD is equilateral.
Construct a rhombus whose side is 5 cm and one angle is of 60°.
