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प्रश्न
Draw a rhombus, having each side of length 3.5 cm and one of the angles as 40°.
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उत्तर
1. Draw a line segment AB of 3.5 cm.
2. Draw \[\angle\] BAX equal to 40\[°\]
3. With A as centre and the radius equal to AB, cut AD at 3.5 cm.
4. With D as centre, cut an arc of radius 3.5 cm.
5. With B as centre, cut an arc of radius 3.5 cm. This arc cuts the arc of step 4 at C.
6. Join DC and BC.
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संबंधित प्रश्न
Two opposite angles of a parallelogram are (3x − 2)° and (50 − x)°. Find the measure of each angle of the parallelogram.
Two adjacent angles of a parallelogram are as 1 : 2. Find the measures of all the angles of the parallelogram.
ABCD is a parallelogram in which ∠A = 70°. Compute ∠B, ∠C and ∠D.
The sum of two opposite angles of a parallelogram is 130°. Find all the angles of the parallelogram.
Two adjacent sides of a parallelogram are 4 cm and 3 cm respectively. Find its perimeter.
In the following Figure ABCD is a arallelogram, CE bisects ∠C and AF bisects ∠A. In each of the following, if the statement is true, give a reason for the same:
(i) ∠A = ∠C
(ii) \[\angle FAB = \frac{1}{2}\angle A\]
(iii) \[\angle DCE = \frac{1}{2}\angle C\]
(iv) \[\angle CEB = \angle FAB\]
(v) CE || AF
Fill in the blank, in the following, so as to make the statement true:
The diagonals of a rhombus ...... each other at ...... angles.
Construct a rhombus whose diagonals are of length 10 cm and 6 cm.
A quadrilateral whose all sides are equal, opposite angles are equal and the diagonals bisect each other at right angles is a ______.
ABCD is a rhombus such that the perpendicular bisector of AB passes through D. Find the angles of the rhombus.
Hint: Join BD. Then ∆ABD is equilateral.
