Advertisements
Advertisements
प्रश्न
Construct ∆ABC such that m∠A = 55°, m∠B = 60°, and l(AB) = 5.9 cm.
Advertisements
उत्तर

Steps of construction:
- Draw seg AB of length 5.9 cm.
- Draw ray AD such that ∠BAD = 55°.
- Draw ray BE such that ∠ABE = 60°.
- Name the point of intersection of ray AD and BE as C.
Therefore, △ABC is the required triangle.
संबंधित प्रश्न
Choose the lengths of the sides yourself and draw one equilateral, one isosceles and one scalene triangle.
Draw triangle with the measures given below.
In ∆ NTS, m ∠T = 40°, l(NT) = l(TS) = 5 cm
Construct a triangle of the measures given below.
In ∆MNP, l(NP) = 5.2 cm, m∠N = 70°, m ∠P = 40°
Construct a triangle of the measures given below.
In ∆ABC, l(AC) = 7.5 cm, m ∠ABC = 90°, l(BC) = 5.5 cm.
Construct ∆EFG from the given measures. l(FG) = 5 cm, m∠EFG = 90°, l(EG) = 7 cm.
Construct a right-angled triangle in which: QP = QR and hypotenuse PR = 7 cm
Construct an equilateral triangle using the given data: Altitude OM = 5.8 cm
Construct a triangle PQR with PQ = 5.4 cm, QR = 4.6 cm and ∠Q = 60°. Draw the perpendicular PS at QR, measure the lengths of SP and SQ,
For constructing △XYZ where XY = 6 cm, YZ = 5 cm, and XZ = 4 cm, which construction method should be used?
In Construction of triangle ABC where AB = 3 cm, BC = 5 cm, and ∠ABC = 60°, which side must be drawn first as the base?
