हिंदी

Consider the carbon compounds having following molecular formula: (i) C3H6 (ii) C3H8 (iii) C4H6 (iv) C6H6 (v) C6H12 (i) State the number of double covalent bonds present in C3H8.

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प्रश्न

Consider the carbon compounds having following molecular formula:

(i) C3H6 (ii) C3H8 (iii) C4H6 (iv) C6H6 (v) C6H12

  1. State the number of double covalent bonds present in C3H8.
  2. Write the formula of first member of the homologous series to which the carbon compound C4H6 belongs.
  3. Which one of the above compounds forms a ring structure of carbon atoms?
  4. Identify, which of the above compounds, is a member of alkane series.
संक्षेप में उत्तर
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उत्तर

(a) There are nine covalent bonds.

(b) C4H6 is an alkyne, The alkynes are a group of chemical compounds with carbon and hydrogen at least one triple bond. With a general molecular formula of Cn H2n-2, where n is any integer higher than 1, the group of compounds is a homologous series.
The first member of this homologous series is ethyne (C2H2). 
\[\ce{H - C = C - H}\]

(c) C6H6 (Benzene) will form the ring. The structure features triple-alternate double bonds and a six-carbon ring, which is symbolised by a hexagon.

(d) C3H8 is an alkane as it has each carbon bonded to four other atoms through single covalent bonds and follow general formula Cn H2n+2.

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2021-2022 (March) Outside Delhi Set 3

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संबंधित प्रश्न

Write the next homologue of the following: C4H6


Give the molecular formula of one homologue of the following:

C3H6

 


Study the different conclusions drawn by students of a class on the basis of observations of preserved/available specimens of plants and animals.

I. Potato and sweet potato are analogous organs in plants.

II. Wings of insects and wings of birds are homologous organs in animals.

III. Wings of insects and wings of bats are analogous organs in animals.

IV. Thorns of citrus and tendrils of cucurbita are analogous organs in plants.

The correct conclusions are:

(A) I, and II

(B) II and IV

(C) I and III

(D) III and IV


Define homologous series of organic compounds. List its two characteristics. Write the name and formula of the first member of the series of alkenes.


What is a homologous series?


Assertion (A): In a homologous series of alcohols, the formula for the second member is C2H5OH and the third member is C3H7OH.
Reason (R): The difference between the molecular masses of the two consecutive members of a homologous series is 144.


Saturated hydrocarbon : Single bond : : Unsaturated hydrocarbon : _______


Complete the following table for the homologous series of alkanes.

Name Molecular formula Condensed structural formula Number of carbon atom Number of -CH2- units Boiling point °C
Methane CH4 CH4 1 1 -162
Ethane C2H6 CH3–CH3 2 2 -88.5
Propane C3H8 CH3–CH2–CH3 3 3 -42
Butane C4H10 CH3–CH2–CH2–CH3 ______ ______ 0
Pentane C5H12 CH3–CH2–CH2–CH2–CH3 ______ ______ 36
Hexane C6H14 CH3–CH2–CH2–CH2–CH2–CH3 ______ ______ 69

Name the following organic compound:

The first homologue whose general formula is CnH2n.


Consider the following molecular formulae of carbon compounds:

(i) CH3COOH (ii) CH3OH (iii) C2H6 (iv) C3H4 (v) C4H

  1. Which one of these compounds belongs to homologous series of alcohols?
  2. Identify the compound having triple bond between carbon-carbon atoms.
  3. Write the molecular formula of the first member of the homologous series to which CH3COOH belongs.
  4. Write the general formula of the series to which the compound C4H8 belongs.

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