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Choose the correct option: Energy stored in a capacitor and dissipated during charging a capacitor bear a ratio. - Physics

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प्रश्न

Choose the correct option:

Energy stored in a capacitor and dissipated during charging a capacitor bear a ratio.

विकल्प

  • 1 : 1

  • 1 : 2

  • 2 : 1

  • 1 : 3

MCQ
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उत्तर

1 : 1

Explanation:

The potential energy stored in the capacitor equals the work done in charging the capacitor. The capacitor is charged by working against the existing electric field between the two plates.

Denote the charge stored by the capacitor of capacitance C when it is fully charged as Q. Denote the battery voltage as V.

The potential energy U, stored in the capacitor, can be represented as:

U = `1/2 "CV"^2`

The work done by battery W, in supplying charge Q can be represented as:

W = QV

⇒ W = (CV)V

⇒ W = CV2

Therefore, the energy dissipated during charging H equals the difference between W and U.

H = W – U

H = `"CV"^2 - 1/2 "CV"^2`

H = `1/2 "CV"^2`

The ratio of and is calculated as follows:

`"U"/"H" = (1/2 "CV"^2)/(1/2 "CV"^2)`

`"U"/"H" = 1/1` i.e. 1 : 1

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अध्याय 8: Electrostatics - Exercises [पृष्ठ २१२]

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बालभारती Physics [English] Standard 12 Maharashtra State Board
अध्याय 8 Electrostatics
Exercises | Q 1.3 | पृष्ठ २१२

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