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प्रश्न
Assertion: IUPAC name of the compound
\[\begin{array}{cc}
\ce{CH3 - CH - O - CH2 - CH2 - CH3}\\
|\phantom{....................}\\
\ce{CH3}\phantom{.................}
\end{array}\] is 2-Ethoxy-2-methylethane.
Reason: In IUPAC nomenclature, ether is regarded as hydrocarbon derivative in which a hydrogen atom is replaced by —OR or —OAr group [where R = alkyl group and Ar = aryl group]
विकल्प
Assertion and reason both are correct and reason is correct explanation of assertion.
Assertion and reason both are wrong statements.
Assertion is correct statement but reason is wrong statement.
Assertion is wrong statement but reason is correct statement.
Both assertion and reason are correct statements but reason is not correct explanation of assertion.
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उत्तर
Assertion is wrong statement but reason is correct statement.
Explanation:
IUPAC name of the compound is 2-propoxypropane.
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संबंधित प्रश्न
Write the IUPAC name of the given compound:
Name the following compound according to the IUPAC system.
\[\begin{array}{cc}
\phantom{.....................................}\ce{CH2OH}\\
\phantom{............................}|\\
\ce{CH3 - CH - CH2 - CH - CH - CH3}\\
|\phantom{....................}|\phantom{............}\\
\ce{CH3}\phantom{..............}\ce{OH}\phantom{.........}\\
\end{array}\]
Write the IUPAC name of the following compound:
\[\begin{array}{cc}
\ce{CH3 - CH - CH - CH3}\\
|\phantom{.........}|\phantom{...}\\
\ce{OH}\phantom{....}\ce{OH}\\
\end{array}\]
Write the IUPAC name of the following compound:
\[\begin{array}{cc}
\ce{HO - CH2 - CH - CH2 - OH}\\
|\phantom{...}\\
\ce{OH}\phantom{.}\\
\end{array}\]
Write the IUPAC name of the following compound:
\[\begin{array}{cc}
\ce{CH3 - CH2 - O - CH - CH2 - CH3}\\
\phantom{....}|\\
\phantom{........}\ce{CH3}
\end{array}\]
Give the IUPAC name of the following ether:
What is the action of hot HI on it?
How is phenol converted into the following?
benzoquinone
Give reasons Fluoride ion has higher hydration enthalpy than chloride ion.
Write structural formulae for Cyclohex-2-en-1-ol.
\[\ce{Phenol ->[Zn, dust] 'X' ->[CH3Cl][Anhy. AlCl3] 'Y' ->[Alkaline][KMnO4] 'Z'}\]
The product ‘Z’ is:
IUPAC name of the compound is:
\[\begin{array}{cc}
\ce{CH3-CH-OCH3}\\
|\phantom{....}\\
\ce{CH3}\phantom{..}
\end{array}\]
Match the structures of the compounds given in Column I with the name of the compounds given in Column II.
| Column I | Column II | |
| (i) |  |
(a) Hydroquinone |
| (ii) |  |
(b) Phenetole |
| (iii) |  |
(c) Catechol |
| (iv) |  |
(d) o-Cresol |
| (v) |  |
(e) guinone |
| (vi) |  |
(f) Resorcinol |
| (g) Anisole |
Match the starting materials given in Column I with the products formed by these (Column II) in the reaction with HI.
| Column I | Column II | ||
| (i) | CH3—O—CH3 | (a) |  |
| (ii) | \[\begin{array}{cc} \ce{CH3}\phantom{..................}\\ \backslash\phantom{.............}\\ \ce{CH-O-CH3}\\ /\phantom{..............}\\ \ce{CH3}\phantom{..................} \end{array}\] |
(b) | \[\begin{array}{cc} \ce{CH3}\phantom{....}\\ |\phantom{.......}\\ \ce{CH3-C-I + CH3OH}\\ |\phantom{.......}\\ \ce{CH3}\phantom{....} \end{array}\] |
| (iii) | \[\begin{array}{cc} \ce{CH3}\phantom{.}\\ |\phantom{....}\\ \ce{H3C-C-O-CH3}\\ |\phantom{....}\\ \ce{CH3}\phantom{..} \end{array}\] |
(c) |  |
| (iv) |  |
(d) | CH3—OH + CH3—I |
| (e) | \[\begin{array}{cc} \ce{CH3}\phantom{.....................}\\ \backslash\phantom{.................}\\ \ce{CH-OH + CH3I}\\ /\phantom{.................}\\ \ce{CH3}\phantom{.....................} \end{array}\] |
||
| (f) | \[\begin{array}{cc} \ce{CH3}\phantom{.....................}\\ \backslash\phantom{.................}\\ \ce{CH-I + CH3OH}\\ /\phantom{.................}\\ \ce{CH3}\phantom{.....................} \end{array}\] |
||
| (g) | \[\begin{array}{cc} \ce{CH3}\phantom{....}\\ |\phantom{.......}\\ \ce{CH3-C-OH + CH3I}\\ |\phantom{.......}\\ \ce{CH3}\phantom{....} \end{array}\] |
Assertion: Like bromination of benzene, bromination of phenol is also carried out in the presence of Lewis acid.
Reason: Lewis acid polarises the bromine molecule.
Assertion: Phenol forms 2, 4, 6 – tribromophenol on treatment with \[\ce{Br2}\] in carbon disulphide at 273 K.
Reason: Bromine polarises in carbon disulphide.
How can phenol be converted to aspirin?
Draw structure of the following compound.
2-Methoxypropane
Write structural formulae for:
Salicylic acid
Write the IUPAC name.
\[\begin{array}{cc}
\phantom{................}\ce{CH3}\\
\phantom{.............}|\\
\ce{CH3 - CH - CH - C -CH3}\\
\phantom{.}|\phantom{......}|\phantom{......}|\\
\phantom{....}\ce{CH3\phantom{...}\ce{OH}\phantom{...}\ce{CH3}}\
\end{array}\]
