Advertisements
Advertisements
प्रश्न
Area of triangle MNO in the following figure is ______.
विकल्प
`1/2` MN × NO
`1/2` NO × MO
`1/2` MN × OQ
`1/2` NO × OQ
Advertisements
उत्तर
Area of triangle MNO in the following figure is `underlinebb(1/2 NO xx OQ)`.
Explanation:
MNO is a triangle
We know that, area of triangle = `1/2` (base × height)
= `1/2` × NO × OQ
APPEARS IN
संबंधित प्रश्न
If the points A(−2, 1), B(a, b) and C(4, −1) are collinear and a − b = 1, find the values of a and b.
Find the area of a triangle whose vertices are A(3, 2), B (11, 8) and C(8, 12).
The vertices of ∆ABC = are A (4, 6), B(1, 5) and C(7, 2). A line is drawn to intersect sides AB and AC at D and E respectively such that `\frac{AD}{AB}=\frac{AE}{AC}=\frac{1}{4}` .Calculate the area of ∆ADE and compare it with the area of ∆ABC
Find the area of the following triangle:
Find the area of the quadrilaterals, the coordinates of whose vertices are
(1, 2), (6, 2), (5, 3) and (3, 4)
Find the area of the blades of thc magnetic compass shown in Fig.. 12.27. (Take √11 = 3.32).
Ratio of areas of ∆MNO, ∆MOP and ∆MPQ in the following figure is ______.
Area of a right-angled triangle is 30 cm2. If its smallest side is 5 cm, then its hypotenuse is ______.
If area of a triangular piece of cardboard is 90 cm2, then the length of altitude corresponding to 20 cm long base is ______ cm.
Find the missing value:
| Base | Height | Area of Triangle |
| 22 cm | ______ | 170.5 cm2 |
