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An unknown alcohol is treated with Lucas reagent. Explain how you will determine whether the alcohol is primary, secondary or tertiary. Indicate by chemical equation the reaction

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प्रश्न

An unknown alcohol is treated with Lucas reagent. Explain how you will determine whether the alcohol is primary, secondary or tertiary. Indicate by chemical equation the reaction between isopropyl alcohol and Lucas reagent.

संक्षेप में उत्तर
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उत्तर

Primary, secondary and tertiary alcohols can be distinguished from each other in the laboratory using Lucas reagent (conc. HCl and ZnCl2).

  1. An unknown alcohol is treated with Lucas reagent.
    The reaction involved is: \[\ce{R - OH ->[HCl][ZnCl2] R - Cl}\]
  2. Depending on the observation an unknown alcohol can be identified as primary, secondary or tertiary.
    Test Observation Inference
    Unknown Alcohol + Lucas reagent Reagent turns turbid on heating. Primary alcohol is present.
    Unknown Alcohol + Lucas reagent Reagent turns turbid slowly, without heating. Secondary alcohol is present.
    Unknown Alcohol + Lucas reagent Reagent turns turbid immediately, without heating. Tertiary alcohol is present.
  3. The reaction between isopropyl alcohol and Lucas reagent can be given as:
    \[\begin{array}{cc}
    \ce{CH3 - CH - CH3 + HCl + ZnCl2 -> CH3 - CH - CH3}\\
    \phantom{..}|\phantom{......................................}|\phantom{..}\\
    \phantom{.....}\ce{\underset{\text{Isopropyl alcohol (2° alcohol)}}{OH} \phantom{....................}\underset{\text{Isopropyl chloride}}{Cl}}\phantom{........}
    \end{array}\]
    The reagent will turns turbid slowly, without heating.
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अध्याय 11: Alcohols, Phenols and Ethers - Short Answer Questions (Type-II)

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एससीईआरटी महाराष्ट्र Chemistry [English] Standard 12 Maharashtra State Board
अध्याय 11 Alcohols, Phenols and Ethers
Short Answer Questions (Type-II) | Q 2

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